Is there a way to calculate the actual physical width & height from that?
For example if you had a yardstick and you had the front of the lens parallel with the yardstick, then aligned the left side of the frame with the end of the yardstick (as close as possible being able to focus) & took a picture.
Looking at the picture the measurement on the right side of the frame should be the measurement I'm trying to figure out.
I think I know what you are asking. At closest focus distance the real size is about 11 1/2in X 7 3/4in. That's the size you can see. Rent one for a weekend. You will like it.
What are you talking about...width and height? The distance is from the front of the lens to your subject. It dose not care how high your subject is or how wide it is... it is one directional...get it? If your subject is 20 feet tall and you want to shoot the top...get a ladder and clip up..just make sure you are at the proper distance from the subject. Same principle if it is 20 feet wide. Go get the any lens and you can do the same test ~X(
Not sure what you are trying to accomplish here...do I dare to ask: what is it you are trying to take a picture off?
Post edited by Golf007sd on
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Quasar was clearly asking for the area. Answering him with a distance is not his fault. There's also nothing to test, Nikon already gives the maximal scale in the lens' specification. Nikon gives a scale of 1/8 (=0.125) for the 1.8 and 0.12 for the 1.4G
The width or the height of the sensor divided by this scale gives you the minimal possible area. FX sensor and 1.4: 23.9mm/0.12= 199.16mm height 36mm/0.12= 300mm width
What are you talking about...width and height? The distance is from the front of the lens to your subject. It dose not care how high your subject is or how wide it is... it is one directional...get it? If your subject is 20 feet tall and you want to shoot the top...get a ladder and clip up..just make sure you are at the proper distance from the subject. Same principle if it is 20 feet wide. Go get the any lens and you can do the same test ~X(
Not sure what you are trying to accomplish here...do I dare to ask: what is it you are trying to take a picture off?
I want to do some copy stand work, taking pictures of old silver photos which can't be scanned. Some of them are smaller and I was contemplating also buying the 105mm Micro but I've already laid out almost $5,000 on gear in the last week so if I could get away with the 85mm which is sharper and I've already ordered then I can put off the 105mm Micro until later (possibly wait for a sale ).
Quasar was clearly asking for the area. Answering him with a distance is not his fault. There's also nothing to test, Nikon already gives the minimal scale in the lens' specification. Nikon gives a scale of 1/8 (=0.125) for the 1.8 and 0.12 for the 1.4G
The width or the height of the sensor divided by this scale gives you the minimal possible area. FX sensor and 1.4: 23.9mm/0.12= 199.16mm height 36mm/0.12= 300mm width
so roughly 11.81" x 7.87" for the 1.4G and 11.34" x 7.53" for the 1.8G.
Thanks, that's what I was trying to figure out. Was that somewhere on Nikon's site and I just overlooked it?
Comments
Not the distance, but the actual size.
An easy test would be to lie a ruler flat and point the camera straight down at it getting as close as possible while still being able to focus.
Though perhaps it might require two rulers next to each other.
Would anyone with a FX camera and a 1.8G and/or 1.4G be kind enough to try this & post the result?
Much thanks
Thanks, but I'm curious what the smallest amount of surface area they can focus on, on their own is.
The 85 1.4G -- .85M (2.8 feet)
If it's the area is that cubic feet? or width or height?
Thanks
AF-S NIKKOR 85mm f/1.8G 2.62 feet
These are the distance from the film plane to the subject.
Is there a way to calculate the actual physical width & height from that?
For example if you had a yardstick and you had the front of the lens parallel with the yardstick, then aligned the left side of the frame with the end of the yardstick (as close as possible being able to focus) & took a picture.
Looking at the picture the measurement on the right side of the frame should be the measurement I'm trying to figure out.
What are you talking about...width and height? The distance is from the front of the lens to your subject. It dose not care how high your subject is or how wide it is... it is one directional...get it? If your subject is 20 feet tall and you want to shoot the top...get a ladder and clip up..just make sure you are at the proper distance from the subject. Same principle if it is 20 feet wide. Go get the any lens and you can do the same test ~X(
Not sure what you are trying to accomplish here...do I dare to ask: what is it you are trying to take a picture off?
Nikon gives a scale of 1/8 (=0.125) for the 1.8 and 0.12 for the 1.4G
The width or the height of the sensor divided by this scale gives you the minimal possible area.
FX sensor and 1.4: 23.9mm/0.12= 199.16mm height 36mm/0.12= 300mm width
Thanks, that's what I was trying to figure out. Was that somewhere on Nikon's site and I just overlooked it?
http://imaging.nikon.com/lineup/lens/singlefocal/normal/af-s_nikkor85mmf_18g/index.htm